职业IT人-IT人生活圈

 找回密码
 成为会员
搜索
查看: 1510|回复: 0

用SQL数据库批量插入数据简介

[复制链接]
cayean 发表于 2006-12-22 23:45 | 显示全部楼层 |阅读模式
来源:赛迪网 曾进

最近忙于公司BI软件性能测试,这几天主要测试CUBE采用ROLAP下,PA的并发和稳定性。涉及表和维度,立方:事实表sales_fact_1997,维度表time_by_day;立方:sales。修改内容:删除原来的TIME维度,新建TIME维度,修改SALES立方。
数据插入:

1、事实数据插入:通过DTS加调度实现将sales_fact_1997的数据进行复制。频率为每分钟10000条。主要用到的SQL语句:select top 10000 * from sales_fact_1997

2、维度数据插入:通过SQL语句插入数据到time_by_day.

测试用到的SQL语句:

1、单条插入


INSERT INTO time_by_day

(time_id, the_date, the_year, month_of_year, quarter,day_of_month)

VALUES (\'1101\', \'1999-10-1\', \'1999\', \'10\', \'Q4\',\'1\')


2、单条插入:


INSERT INTO time_by_day

(time_id, the_date, the_year, month_of_year, quarter, day_of_month)

SELECT TOP 1 time_id + 1 AS time_id, the_date + 1 AS the_date, YEAR(the_date + 1)

AS the_year, MONTH(the_date + 1) AS month_of_year, { fn QUARTER(the_date + 1)

} AS quarter, DAY(the_date + 1) AS day_of_month

FROM time_by_day

ORDER BY time_id DESC


3、循环插入:


DECLARE @MyCounter INT

SET @MyCounter = 0            /*设置变量*/

WHILE (@MyCounter < 2)     /*设置循环次数*/

BEGIN

WAITFOR DELAY \'000:00:10\'   /*延迟时间10秒*/

INSERT INTO time_by_day
(time_id, the_date, the_year, month_of_year, quarter, day_of_month)

SELECT TOP 1 time_id + 1 AS time_id, the_date + 1 AS the_date, YEAR(the_date + 1)

AS the_year, MONTH(the_date + 1) AS month_of_year, { fn QUARTER(the_date + 1)

} AS quarter, DAY(the_date + 1) AS day_of_month

FROM time_by_day

ORDER BY time_id DESC


SET @MyCounter = @MyCounter + 1

END


4、插入以时间为变量的数据


DECLARE @MyCounter INT

declare @the_date datetime

SET @MyCounter = 0

SET @the_date = \'1999-1-4\'

WHILE (@MyCounter < 200000)

BEGIN

WAITFOR DELAY \'000:00:10\'

/*INSERT INTO time_by_day

(time_id, the_date, the_year, month_of_year, quarter, day_of_month)

SELECT TOP 1 time_id + 1 AS time_id, the_date + 1 AS the_date, YEAR(the_date + 1)

AS the_year, MONTH(the_date + 1) AS month_of_year, { fn QUARTER(the_date + 1)

} AS quarter, DAY(the_date + 1) AS day_of_month

FROM time_by_day

ORDER BY time_id DESC

*/

insert into time_by_day (time_id,the_date)values(\'371\',@the_date)

SET @the_date = @the_date + 1

SET @MyCounter = @MyCounter + 1

END
您需要登录后才可以回帖 登录 | 成为会员

本版积分规则

QQ|手机版|小黑屋|网站帮助|职业IT人-IT人生活圈 ( 粤ICP备12053935号-1 )|网站地图
本站文章版权归原发布者及原出处所有。内容为作者个人观点,并不代表本站赞同其观点和对其真实性负责,本站只提供参考并不构成任何投资及应用建议。本站是信息平台,网站上部分文章为转载,并不用于任何商业目的,我们已经尽可能的对作者和来源进行了通告,但是能力有限或疏忽造成漏登,请及时联系我们,我们将根据著作权人的要求立即更正或者删除有关内容。

GMT+8, 2024-5-18 12:36 , Processed in 0.119122 second(s), 20 queries , Gzip On.

Powered by Discuz! X3.4

Copyright © 2001-2021, Tencent Cloud.

快速回复 返回顶部 返回列表